What is the f(x)=(x^2+2x)/1+(3x-3x^2)/(3x+1) ?

The f(x)=(x^2+2x)/1+(3x-3x^2)/(3x+1) is

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f(x)=(x^2+2x)/1+(3x-3x^2)/(3x+1)

f (x) = \frac{x ^{2} + 2 x}{1} + \frac{3 x - 3 x ^{2}}{3 x + 1}

Domain : x < - \frac{1}{3} or x > - \frac{1}{3}

Range : - \infty < f (x) < \infty

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Vertical x = - \frac{1}{3}

Extreme Points : Minimum (- 1, 2)

Interval Notation

Domain : (- \infty, - \frac{1}{3}) \cup (- \frac{1}{3}, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{x ^{2} + 2 x}{1} + \frac{3 x - 3 x ^{2}}{3 x + 1} : x < - \frac{1}{3} or x > - \frac{1}{3}

Range of

\frac{x ^{2} + 2 x}{1} + \frac{3 x - 3 x ^{2}}{3 x + 1} : - \infty < f (x) < \infty

Axis interception points of

\frac{x ^{2} + 2 x}{1} + \frac{3 x - 3 x ^{2}}{3 x + 1} :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{x ^{2} + 2 x}{1} + \frac{3 x - 3 x ^{2}}{3 x + 1} :

Vertical

: x = - \frac{1}{3}

Extreme Points of

\frac{x ^{2} + 2 x}{1} + \frac{3 x - 3 x ^{2}}{3 x + 1} :

Minimum

(- 1, 2)

What is the f(x)=(x^2+2x)/1+(3x-3x^2)/(3x+1) ?
The f(x)=(x^2+2x)/1+(3x-3x^2)/(3x+1) is