What is the domain of f(x)=((x^2))/(3x-1) ?

The domain of f(x)=((x^2))/(3x-1) is x 1/3

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domain of f(x)=((x^2))/(3x-1)

domain

f (x) = \frac{( x ^{2} )}{3 x - 1}

x < \frac{1}{3} or x > \frac{1}{3}

Interval Notation

(- \infty, \frac{1}{3}) \cup (\frac{1}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{3}

The function domain

x < \frac{1}{3} or x > \frac{1}{3}

cos (2 x + 5)

f (x) = \frac{1}{x ^{2} - 1}

f (x) = \frac{10 x ^{2} - 18 x}{15 x - 27}

\frac{x ^{2} - 9 x + 39}{x - 7}

2 x ln (x) + x

What is the domain of f(x)=((x^2))/(3x-1) ?
The domain of f(x)=((x^2))/(3x-1) is x< 1/3 \lor x> 1/3