What is the inverse of 1/2 (x+4)^2-2 ?

The inverse of 1/2 (x+4)^2-2 is sqrt(2x+4)-4,-sqrt(2x+4)-4

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inverse of 1/2 (x+4)^2-2

inverse

\frac{1}{2} (x + 4)^{2} - 2

2 x + 4 - 4, - 2 x + 4 - 4

Solution steps

y = \frac{1}{2} (x + 4)^{2} - 2

Replace

x

with

y

x = \frac{1}{2} (y + 4)^{2} - 2

Solve for

y, x = \frac{1}{2} (y + 4)^{2} - 2

2 x + 4 - 4, - 2 x + 4 - 4

f (x) = 5 + 4 x - x^{3}

y = (x + 2)^{2}

(2, - 5), (6, 7)

(2, 4), (3, 7)

(3.5) (5.3)

What is the inverse of 1/2 (x+4)^2-2 ?
The inverse of 1/2 (x+4)^2-2 is sqrt(2x+4)-4,-sqrt(2x+4)-4