What is the domain of f(x)=-7/(2x^{3/2)} ?

The domain of f(x)=-7/(2x^{3/2)} is x>0

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domain of f(x)=-7/(2x^{3/2)}

domain

f (x) = - \frac{7}{2 x ^{\frac{3}{2}}}

x > 0

Interval Notation

(0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x > 0

(2.8) (1.3)

f (x) = 3 sin (2 x)

\frac{x ^{2}}{x ^{2} - 81}

f (x) = x^{2} e^{x}

f (x) = - x^{3} + 6 x^{2}

What is the domain of f(x)=-7/(2x^{3/2)} ?
The domain of f(x)=-7/(2x^{3/2)} is x>0