What is the critical f(x)=x^4-16x^3+64x^2 ?

The critical f(x)=x^4-16x^3+64x^2 is x=0,x=4,x=8

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critical f(x)=x^4-16x^3+64x^2

critical points

f (x) = x^{4} - 16 x^{3} + 64 x^{2}

x = 0, x = 4, x = 8

Solution steps

x^{4} - 16 x^{3} + 64 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 4, x = 8

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 16 x^{3} + 64 x^{2} : - \infty < x < \infty

All critical points are in domain

x = 0, x = 4, x = 8

- x^{2} - 8 x - 21

y = - 2 x^{2} + 8 x - 5

ln (x + 4)

f (x) = 2 x + 5

f (x) = \frac{x - 4}{3 x + 5}

What is the critical f(x)=x^4-16x^3+64x^2 ?
The critical f(x)=x^4-16x^3+64x^2 is x=0,x=4,x=8