What is the asymptotes of f(x)=(x^2-9)/(x^2-3x+2) ?

The asymptotes of f(x)=(x^2-9)/(x^2-3x+2) is Vertical: x=1,x=2,Horizontal: y=1

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asymptotes of f(x)=(x^2-9)/(x^2-3x+2)

asymptotes

f (x) = \frac{x ^{2} - 9}{x ^{2} - 3 x + 2}

Vertical : x = 1, x = 2, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 9}{x ^{2} - 3 x + 2} : x = 1, x = 2

Horizontal Asymptotes of

\frac{x ^{2} - 9}{x ^{2} - 3 x + 2} : y = 1

Slant Asymptotes of

\frac{x ^{2} - 9}{x ^{2} - 3 x + 2} :

None

Vertical : x = 1, x = 2, Horizontal : y = 1

4 x + 2 y = 8

- - x + 2

f (x) = x^{4} + 3 x^{3}

f (x) = \frac{3 x ^{3} + 2 x + 2}{2 x ^{3} + 5 x - 5}

y = x^{2} + 3 x - 4

What is the asymptotes of f(x)=(x^2-9)/(x^2-3x+2) ?
The asymptotes of f(x)=(x^2-9)/(x^2-3x+2) is Vertical: x=1,x=2,Horizontal: y=1