What is the domain of f(x)=sqrt(-x^2-x+2) ?

The domain of f(x)=sqrt(-x^2-x+2) is -2<= x<= 1

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domain of f(x)=sqrt(-x^2-x+2)

domain

f (x) = - x^{2} - x + 2

- 2 \leq x \leq 1

Interval Notation

[- 2, 1]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 1

The function domain

- 2 \leq x \leq 1

f (x) = \frac{5 x + 2}{x ^{2} + 6 x + 8}

f (x) = (x - 2)

f (x) = \frac{x ^{2} + 5 x + 4}{x ^{2} - 4}

6 x + 8 y = 7 y - 4

f (x) = 4 x - 7

What is the domain of f(x)=sqrt(-x^2-x+2) ?
The domain of f(x)=sqrt(-x^2-x+2) is -2<= x<= 1