What is the general solution for roots ((1+sin(x)))/n ?

The general solution for roots ((1+sin(x)))/n is x=(3pi)/2+2pik

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roots ((1+sin(x)))/n

roots

\frac{( 1 + sin ( x ) )}{n}

x = \frac{3 π}{2} + 2 πk

Solution steps

\frac{( 1 + sin ( x ) )}{n}

The roots are the intercepts with the x-axis

(y = 0)

\frac{( 1 + sin ( x ) )}{n} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

1 + sin (x) = 0

Move

1

to the right side

sin (x) = - 1

General solutions for

sin (x) = - 1

x = \frac{3 π}{2} + 2 πk

What is the general solution for roots ((1+sin(x)))/n ?
The general solution for roots ((1+sin(x)))/n is x=(3pi)/2+2pik