What is the asymptotes of f(x)=(x^2-2x-1)/(2x-8) ?

The asymptotes of f(x)=(x^2-2x-1)/(2x-8) is Vertical: x=4,Slant: y= 1/2 x+1

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asymptotes of f(x)=(x^2-2x-1)/(2x-8)

asymptotes

f (x) = \frac{x ^{2} - 2 x - 1}{2 x - 8}

Vertical : x = 4, Slant : y = \frac{1}{2} x + 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 2 x - 1}{2 x - 8} : x = 4

Horizontal Asymptotes of

\frac{x ^{2} - 2 x - 1}{2 x - 8} :

None

Slant Asymptotes of

\frac{x ^{2} - 2 x - 1}{2 x - 8} : y = \frac{1}{2} x + 1

Vertical : x = 4, Slant : y = \frac{1}{2} x + 1

f (x) = \frac{8 x}{5 x - 6}

f (x) = x + 4

f (x) = x + sin (x)

f (x) = 3 x - 6

f (x) = - 2 x^{2} + 5

What is the asymptotes of f(x)=(x^2-2x-1)/(2x-8) ?
The asymptotes of f(x)=(x^2-2x-1)/(2x-8) is Vertical: x=4,Slant: y= 1/2 x+1