What is the y=((sqrt(a^2+x^2)))/x ?

The y=((sqrt(a^2+x^2)))/x is Parity: Odd Inverse: (asqrt(x^2-1))/(x^2-1),-(asqrt(x^2-1))/(x^2-1)

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y=((sqrt(a^2+x^2)))/x

y = \frac{( a ^{2} + x ^{2} )}{x}

Parity : Odd

Inverse : \frac{a x ^{2} - 1}{x ^{2} - 1}, - \frac{a x ^{2} - 1}{x ^{2} - 1}

Solution steps

Parity of

\frac{a ^{2} + x ^{2}}{x} :

Odd

Inverse of

\frac{a ^{2} + x ^{2}}{x} : \frac{a x ^{2} - 1}{x ^{2} - 1}, - \frac{a x ^{2} - 1}{x ^{2} - 1}

What is the y=((sqrt(a^2+x^2)))/x ?
The y=((sqrt(a^2+x^2)))/x is Parity: Odd<br/>Inverse: (asqrt(x^2-1))/(x^2-1),-(asqrt(x^2-1))/(x^2-1)