What is the domain of sqrt(x+1)+1/(x^2+1) ?

The domain of sqrt(x+1)+1/(x^2+1) is x>=-1

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domain of sqrt(x+1)+1/(x^2+1)

domain

x + 1 + \frac{1}{x ^{2} + 1}

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

4 x - 3 y = - 18

f (x) = 3 (x^{\frac{1}{2}} - 3)

x - 12

f (x) = - \frac{7}{2 x x}

f (x) = \frac{5}{x + 3}

What is the domain of sqrt(x+1)+1/(x^2+1) ?
The domain of sqrt(x+1)+1/(x^2+1) is x>=-1