What is the critical f(x)=(x+2)^2(x-1)^4 ?

The critical f(x)=(x+2)^2(x-1)^4 is x=-2,x=-1,x=1

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critical f(x)=(x+2)^2(x-1)^4

critical points

f (x) = (x + 2)^{2} (x - 1)^{4}

x = - 2, x = - 1, x = 1

Solution steps

(x + 2)^{2} (x - 1)^{4}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

(x + 2)^{2} (x - 1)^{4} : - \infty < x < \infty

All critical points are in domain

x = - 2, x = - 1, x = 1

x + 10

y + 3 = 2 (x - 2)

2 x + 3

\frac{2 x ^{2} - 8 x}{x ^{2} - 7 x + 12}

2 y = 3 x + 7

What is the critical f(x)=(x+2)^2(x-1)^4 ?
The critical f(x)=(x+2)^2(x-1)^4 is x=-2,x=-1,x=1