What is the asymptotes of y=(2x^2-2x-8)/((x+4)^2) ?

The asymptotes of y=(2x^2-2x-8)/((x+4)^2) is Vertical: x=-4,Horizontal: y=2

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asymptotes of y=(2x^2-2x-8)/((x+4)^2)

asymptotes

y = \frac{2 x ^{2} - 2 x - 8}{( x + 4 ) ^{2}}

Vertical : x = - 4, Horizontal : y = 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} - 2 x - 8}{( x + 4 ) ^{2}} : x = - 4

Horizontal Asymptotes of

\frac{2 x ^{2} - 2 x - 8}{( x + 4 ) ^{2}} : y = 2

Slant Asymptotes of

\frac{2 x ^{2} - 2 x - 8}{( x + 4 ) ^{2}} :

None

Vertical : x = - 4, Horizontal : y = 2

12 x + 3

sin (4 x + π)

\frac{x - 2}{x + 3}

f (x) = \frac{x - 3}{x ^{2} + 2 x + 14}

f (x) = \frac{x - 2}{x ^{2} + 4 x + 4}

What is the asymptotes of y=(2x^2-2x-8)/((x+4)^2) ?
The asymptotes of y=(2x^2-2x-8)/((x+4)^2) is Vertical: x=-4,Horizontal: y=2