What is the inverse of f(x)=(4x-5)/(8x+1) ?

The inverse of f(x)=(4x-5)/(8x+1) is (-5-x)/(4(-1+2x))

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inverse of f(x)=(4x-5)/(8x+1)

inverse

f (x) = \frac{4 x - 5}{8 x + 1}

\frac{- 5 - x}{4 ( - 1 + 2 x )}

Solution steps

y = \frac{4 x - 5}{8 x + 1}

Replace

x

with

y

x = \frac{4 y - 5}{8 y + 1}

Solve for

y, x = \frac{4 y - 5}{8 y + 1}

\frac{- 5 - x}{4 ( - 1 + 2 x )}

x - 6 y = - 12

f (x) = \frac{x - 6}{x - 2}

f (x) = \frac{- 46}{( 0.69 x ^{2} )}

(- 7, - 9), (6, 3)

x sec^{2} (π x)

What is the inverse of f(x)=(4x-5)/(8x+1) ?
The inverse of f(x)=(4x-5)/(8x+1) is (-5-x)/(4(-1+2x))