What is the asymptotes of f(x)= 5/(x^2-36) ?

The asymptotes of f(x)= 5/(x^2-36) is Vertical: x=-6,x=6,Horizontal: y=0

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asymptotes of f(x)= 5/(x^2-36)

asymptotes

f (x) = \frac{5}{x ^{2} - 36}

Vertical : x = - 6, x = 6, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{5}{x ^{2} - 36} : x = - 6, x = 6

Horizontal Asymptotes of

\frac{5}{x ^{2} - 36} : y = 0

Slant Asymptotes of

\frac{5}{x ^{2} - 36} :

None

Vertical : x = - 6, x = 6, Horizontal : y = 0

a sy m pt o t es f (x) = \frac{4}{( x - 3 ) ^{2}}

a sy m pt o t es f (x) = \frac{x}{( 1 + x ^{2} )}

a sy m pt o t es y = 2^{x + 3} - 1

a sy m pt o t es \frac{x ^{2} - 10 x + 25}{x - 3}

a sy m pt o t es f (x) = (\frac{4}{5})^{x}

What is the asymptotes of f(x)= 5/(x^2-36) ?
The asymptotes of f(x)= 5/(x^2-36) is Vertical: x=-6,x=6,Horizontal: y=0