What is the asymptotes of h(x)=(x+1)/(x(x-3)) ?

The asymptotes of h(x)=(x+1)/(x(x-3)) is Vertical: x=0,x=3,Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of h(x)=(x+1)/(x(x-3))

asymptotes

h (x) = \frac{x + 1}{x ( x - 3 )}

Vertical : x = 0, x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x + 1}{x ( x - 3 )} : x = 0, x = 3

Horizontal Asymptotes of

\frac{x + 1}{x ( x - 3 )} : y = 0

Slant Asymptotes of

\frac{x + 1}{x ( x - 3 )} :

None

Vertical : x = 0, x = 3, Horizontal : y = 0

- 1 - x^{5}

f (x) = x + x + 8

x - 4 y = - 8

f (x) = \frac{x + 1}{x - 2}

f (x) = - lo g_{5} (x + 2)

What is the asymptotes of h(x)=(x+1)/(x(x-3)) ?
The asymptotes of h(x)=(x+1)/(x(x-3)) is Vertical: x=0,x=3,Horizontal: y=0