What is the asymptotes of f(x)=((x-8)(x+1))/(x^2-9) ?

The asymptotes of f(x)=((x-8)(x+1))/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=1

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asymptotes of f(x)=((x-8)(x+1))/(x^2-9)

asymptotes

f (x) = \frac{( x - 8 ) ( x + 1 )}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{( x - 8 ) ( x + 1 )}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{( x - 8 ) ( x + 1 )}{x ^{2} - 9} : y = 1

Slant Asymptotes of

\frac{( x - 8 ) ( x + 1 )}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 1

a sy m pt o t es 5 y - 5 x + x y - 10 = 0

a sy m pt o t es f (x) = 4^{- x}

a sy m pt o t es f (x) = \frac{( 2 x ^{2} )}{2 x - 8}

a sy m pt o t es \frac{2 e ^{x} + x ^{2}}{x - 1}

a sy m pt o t es f (x) = \frac{14 x ^{2}}{x - 8}

What is the asymptotes of f(x)=((x-8)(x+1))/(x^2-9) ?
The asymptotes of f(x)=((x-8)(x+1))/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=1