What is the asymptotes of f(x)=(1-x^2)/(x^2-9) ?

The asymptotes of f(x)=(1-x^2)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=-1

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asymptotes of f(x)=(1-x^2)/(x^2-9)

asymptotes

f (x) = \frac{1 - x ^{2}}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = - 1

Solution steps

Vertical asymptotes of

\frac{1 - x ^{2}}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{1 - x ^{2}}{x ^{2} - 9} : y = - 1

Slant Asymptotes of

\frac{1 - x ^{2}}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = - 1

a sy m pt o t es f (x) = \frac{x ^{3} - 9 x}{x ^{2} + x - 6}

a sy m pt o t es f (x) = \frac{9 x ^{2} - 36}{x ^{2} - 9}

a sy m pt o t es \frac{5 x ^{3} - 15 x ^{2} + 9 x - 27}{x ^{2} + 9}

a sy m pt o t es \frac{8 x ^{3}}{2 x ^{2} + 1}

a sy m pt o t es f (x) = \frac{x ^{2} - 6 x - 1}{x + 3}

What is the asymptotes of f(x)=(1-x^2)/(x^2-9) ?
The asymptotes of f(x)=(1-x^2)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=-1