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midpoint
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domain of f(x)=(xsqrt(x))/(2x^2-5)inverse of f(x)= 1/(x+9)asymptotes of ((x^2+8x-9))/(x^2+3x-4)range of 2x+1range of f(x)=sqrt(x)+5
Frequently Asked Questions (FAQ)
What is the midpoint (-3,-5),(-0.5,0) ?
The midpoint (-3,-5),(-0.5,0) is (-1.75,-5/2)