What is the asymptotes of f(x)=(x^2+2x+1)/(8x^2-x-9) ?

The asymptotes of f(x)=(x^2+2x+1)/(8x^2-x-9) is Vertical: x= 9/8 ,Horizontal: y= 1/8

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asymptotes of f(x)=(x^2+2x+1)/(8x^2-x-9)

asymptotes

f (x) = \frac{x ^{2} + 2 x + 1}{8 x ^{2} - x - 9}

Vertical : x = \frac{9}{8}, Horizontal : y = \frac{1}{8}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 2 x + 1}{8 x ^{2} - x - 9} : x = \frac{9}{8}

Horizontal Asymptotes of

\frac{x ^{2} + 2 x + 1}{8 x ^{2} - x - 9} : y = \frac{1}{8}

Slant Asymptotes of

\frac{x ^{2} + 2 x + 1}{8 x ^{2} - x - 9} :

None

Vertical : x = \frac{9}{8}, Horizontal : y = \frac{1}{8}

What is the asymptotes of f(x)=(x^2+2x+1)/(8x^2-x-9) ?
The asymptotes of f(x)=(x^2+2x+1)/(8x^2-x-9) is Vertical: x= 9/8 ,Horizontal: y= 1/8