渐近线 f(x)=(15x^3)/(7x^2+1)

解答

渐近线

f (x) = \frac{15 x ^{3}}{7 x ^{2} + 1}

Slant : y = \frac{15}{7} x

求解步骤

\frac{15 x ^{3}}{7 x ^{2} + 1}

的垂直渐近线:

无

\frac{15 x ^{3}}{7 x ^{2} + 1}

的水平渐近线:

无

Slant Asymptotes of

\frac{15 x ^{3}}{7 x ^{2} + 1} : y = \frac{15}{7} x

Slant : y = \frac{15}{7} x

r an g e f (x) = (\frac{2}{7}) (4)^{- x} + 12

d o main f (x) = \frac{1}{∣ x ∣}

s l o p e in t erce pt y = - \frac{5}{4} x - \frac{7}{8}

a sy m pt o t es f (x) = \frac{2 x ^{3} - 2 x ^{2}}{x ^{3} - 9 x}

a sy m pt o t es f (x) = \frac{( 3 x ^{2} - 10 x + 8 )}{x - 5}