What is the line (0,0.042),(60,0.482) ?

The line (0,0.042),(60,0.482) is y=0.00733…x+0.042

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line (0,0.042),(60,0.482)

line

(0, 0.042), (60, 0.482)

y = 0.00733 \dots x + 0.042

Solution steps

Find the line

y = mx + b

passing through

(0, 0.042)

(60, 0.482)

Compute the slope

(0, 0.042), (60, 0.482) : m = 0.00733 \dots

Compute the

y

intercept:

b = 0.042

Construct the line equation

y = mx + b

where

m = 0.00733 \dots

and

b = 0.042

y = 0.00733 \dots x + 0.042

f (x) = 3 x^{2} + 4 x + 1

f (x) = \frac{x - 1}{x ^{2} + 5 x + 10}

f (x) = (\frac{1}{x + 2}) - (\frac{7 x}{x + 2})

y = x^{2} + 6 x + 9

f (x) = x - 13

What is the line (0,0.042),(60,0.482) ?
The line (0,0.042),(60,0.482) is y=0.00733…x+0.042