What is the domain of sqrt(x+6)*(x^2+3) ?

The domain of sqrt(x+6)*(x^2+3) is x>=-6

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domain of sqrt(x+6)*(x^2+3)

domain

x + 6 \cdot (x^{2} + 3)

x \geq - 6

Interval Notation

[- 6, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 6

The function domain

x \geq - 6

f (x) = (x - 3)^{3}

f (x) = - 16 y^{2} + 8 y + 24

f (x) = \frac{3 ( x - 2 )}{x - 1}

f (x) = - 5 x - 4 y = 10

7 x + 6 y = 6

What is the domain of sqrt(x+6)*(x^2+3) ?
The domain of sqrt(x+6)*(x^2+3) is x>=-6