What is the asymptotes of f(x)=(3x^2+10x-48)/(x-5) ?

The asymptotes of f(x)=(3x^2+10x-48)/(x-5) is Vertical: x=5,Slant: y=3x+25

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asymptotes of f(x)=(3x^2+10x-48)/(x-5)

asymptotes

f (x) = \frac{3 x ^{2} + 10 x - 48}{x - 5}

Vertical : x = 5, Slant : y = 3 x + 25

Solution steps

Vertical asymptotes of

\frac{3 x ^{2} + 10 x - 48}{x - 5} : x = 5

Horizontal Asymptotes of

\frac{3 x ^{2} + 10 x - 48}{x - 5} :

None

Slant Asymptotes of

\frac{3 x ^{2} + 10 x - 48}{x - 5} : y = 3 x + 25

Vertical : x = 5, Slant : y = 3 x + 25

What is the asymptotes of f(x)=(3x^2+10x-48)/(x-5) ?
The asymptotes of f(x)=(3x^2+10x-48)/(x-5) is Vertical: x=5,Slant: y=3x+25