What is the domain of arccos((2x+1)/(x-3)) ?

The domain of arccos((2x+1)/(x-3)) is -4<= x<= 2/3

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domain of arccos((2x+1)/(x-3))

domain

arccos (\frac{2 x + 1}{x - 3})

- 4 \leq x \leq \frac{2}{3}

Interval Notation

[- 4, \frac{2}{3}]

Solution steps

Find known functions domain restrictions:

- 4 \leq x \leq \frac{2}{3}

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

- 4 \leq x \leq \frac{2}{3}

f (x) = 7 - 6 x^{2}

f (x) = (x - 1)^{3}

f (x) = \frac{x - 4}{3 x - x ^{2}}

y = 6

f (x) = - 2 x + 6

What is the domain of arccos((2x+1)/(x-3)) ?
The domain of arccos((2x+1)/(x-3)) is -4<= x<= 2/3