What is the asymptotes of f(x)=(4x^2+1)/(2x^2+7x-4) ?

The asymptotes of f(x)=(4x^2+1)/(2x^2+7x-4) is Vertical: x=-4,x= 1/2 ,Horizontal: y=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

asymptotes of f(x)=(4x^2+1)/(2x^2+7x-4)

asymptotes

f (x) = \frac{4 x ^{2} + 1}{2 x ^{2} + 7 x - 4}

Vertical : x = - 4, x = \frac{1}{2}, Horizontal : y = 2

Solution steps

Vertical asymptotes of

\frac{4 x ^{2} + 1}{2 x ^{2} + 7 x - 4} : x = - 4, x = \frac{1}{2}

Horizontal Asymptotes of

\frac{4 x ^{2} + 1}{2 x ^{2} + 7 x - 4} : y = 2

Slant Asymptotes of

\frac{4 x ^{2} + 1}{2 x ^{2} + 7 x - 4} :

None

Vertical : x = - 4, x = \frac{1}{2}, Horizontal : y = 2

What is the asymptotes of f(x)=(4x^2+1)/(2x^2+7x-4) ?
The asymptotes of f(x)=(4x^2+1)/(2x^2+7x-4) is Vertical: x=-4,x= 1/2 ,Horizontal: y=2