Solution
midpoint
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inflection (2x)/(x-1)inflection points distance (-6,-10),(-2,-10)distance inverse of sqrt(x-1)inverse symmetry x^2+y^2=16symmetry domain of-1/(2sqrt(5-x))domain
Frequently Asked Questions (FAQ)
What is the midpoint (-5,3),(1,-3) ?
The midpoint (-5,3),(1,-3) is (-2,0)