What is the inverse of f(x)=(2-x^3)^5 ?

The inverse of f(x)=(2-x^3)^5 is cube root of-\sqrt[5]{x}+2

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inverse of f(x)=(2-x^3)^5

inverse

f (x) = (2 - x^{3})^{5}

Solution steps

y = (2 - x^{3})^{5}

Replace

x

with

y

x = (2 - y^{3})^{5}

Solve for

y, x = (2 - y^{3})^{5}

f (x) = 5 x + 8

f (x) = x^{2} + 4 x + 4

(5.4) (2.1)

f (x) = 3 cos (x), 0 \leq x \leq 2 π

f (x) = lo g_{3} (x - 3)

What is the inverse of f(x)=(2-x^3)^5 ?
The inverse of f(x)=(2-x^3)^5 is cube root of-\sqrt[5]{x}+2