What is the inverse of s/((s+4)(s+8)) ?

The inverse of s/((s+4)(s+8)) is (-12s+1+sqrt(16s^2-24s+1))/(2s),(-12s+1-sqrt(16s^2-24s+1))/(2s)

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inverse of s/((s+4)(s+8))

inverse

\frac{s}{( s + 4 ) ( s + 8 )}

\frac{- 12 s + 1 + 16 s ^{2} - 24 s + 1}{2 s}, \frac{- 12 s + 1 - 16 s ^{2} - 24 s + 1}{2 s}

Solution steps

y = \frac{s}{( s + 4 ) ( s + 8 )}

Replace

s

with

y

s = \frac{y}{( y + 4 ) ( y + 8 )}

Solve for

y, s = \frac{y}{( y + 4 ) ( y + 8 )}

\frac{- 12 s + 1 + 16 s ^{2} - 24 s + 1}{2 s}, \frac{- 12 s + 1 - 16 s ^{2} - 24 s + 1}{2 s}

\frac{7 x}{5 + 9 x}

f (x) = \frac{( - x - 9 )}{( x + 4 )}

f (x) = \frac{x + 8}{x - 8}

f (x) = x^{2} + x - 6

f (x) = x^{3} + 3 x^{2} - 4

What is the inverse of s/((s+4)(s+8)) ?
The inverse of s/((s+4)(s+8)) is (-12s+1+sqrt(16s^2-24s+1))/(2s),(-12s+1-sqrt(16s^2-24s+1))/(2s)