What is the asymptotes of f(x)=(x^2-2x-8)/(x+1) ?

The asymptotes of f(x)=(x^2-2x-8)/(x+1) is Vertical: x=-1,Slant: y=x-3

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asymptotes of f(x)=(x^2-2x-8)/(x+1)

asymptotes

f (x) = \frac{x ^{2} - 2 x - 8}{x + 1}

Vertical : x = - 1, Slant : y = x - 3

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 2 x - 8}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} - 2 x - 8}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} - 2 x - 8}{x + 1} : y = x - 3

Vertical : x = - 1, Slant : y = x - 3

f (x) = 9 x + 8

f (x) = - x^{2} + 2 x + 4

\frac{2 x ^{2} - 2 x - 24}{x ^{2} - 4 x + 3}

5 x - y = 1

(0) (20.2)

What is the asymptotes of f(x)=(x^2-2x-8)/(x+1) ?
The asymptotes of f(x)=(x^2-2x-8)/(x+1) is Vertical: x=-1,Slant: y=x-3