What is the asymptotes of f(x)=(x^2+2x)/(x^2-2x-8) ?

The asymptotes of f(x)=(x^2+2x)/(x^2-2x-8) is Vertical: x=4,Horizontal: y=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

asymptotes of f(x)=(x^2+2x)/(x^2-2x-8)

asymptotes

f (x) = \frac{x ^{2} + 2 x}{x ^{2} - 2 x - 8}

Vertical : x = 4, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 2 x}{x ^{2} - 2 x - 8} : x = 4

Horizontal Asymptotes of

\frac{x ^{2} + 2 x}{x ^{2} - 2 x - 8} : y = 1

Slant Asymptotes of

\frac{x ^{2} + 2 x}{x ^{2} - 2 x - 8} :

None

Vertical : x = 4, Horizontal : y = 1

What is the asymptotes of f(x)=(x^2+2x)/(x^2-2x-8) ?
The asymptotes of f(x)=(x^2+2x)/(x^2-2x-8) is Vertical: x=4,Horizontal: y=1