What is the inverse of sqrt(x^2+9x) ?

The inverse of sqrt(x^2+9x) is (-9+sqrt(81+4x^2))/2 ,(-9-sqrt(81+4x^2))/2

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inverse of sqrt(x^2+9x)

inverse

x^{2} + 9 x

\frac{- 9 + 81 + 4 x ^{2}}{2}, \frac{- 9 - 81 + 4 x ^{2}}{2}

Solution steps

y = x^{2} + 9 x

Replace

x

with

y

x = y^{2} + 9 y

Solve for

y, x = y^{2} + 9 y

\frac{- 9 + 81 + 4 x ^{2}}{2}, \frac{- 9 - 81 + 4 x ^{2}}{2}

f (x) = \frac{( 5 x + 4 )}{x ^{2} + 3 x + 2}

y = \frac{3}{5} x + 9

x^{3} - 27

f (x) = - x^{2} - 2 x - 4

What is the inverse of sqrt(x^2+9x) ?
The inverse of sqrt(x^2+9x) is (-9+sqrt(81+4x^2))/2 ,(-9-sqrt(81+4x^2))/2