What is the asymptotes of f(x)=(x^3-9x)/(3x^2-3x-6) ?

The asymptotes of f(x)=(x^3-9x)/(3x^2-3x-6) is Vertical: x=-1,x=2,Slant: y= 1/3 x+1/3

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asymptotes of f(x)=(x^3-9x)/(3x^2-3x-6)

asymptotes

f (x) = \frac{x ^{3} - 9 x}{3 x ^{2} - 3 x - 6}

Vertical : x = - 1, x = 2, Slant : y = \frac{1}{3} x + \frac{1}{3}

Solution steps

Vertical asymptotes of

\frac{x ^{3} - 9 x}{3 x ^{2} - 3 x - 6} : x = - 1, x = 2

Horizontal Asymptotes of

\frac{x ^{3} - 9 x}{3 x ^{2} - 3 x - 6} :

None

Slant Asymptotes of

\frac{x ^{3} - 9 x}{3 x ^{2} - 3 x - 6} : y = \frac{1}{3} x + \frac{1}{3}

Vertical : x = - 1, x = 2, Slant : y = \frac{1}{3} x + \frac{1}{3}

What is the asymptotes of f(x)=(x^3-9x)/(3x^2-3x-6) ?
The asymptotes of f(x)=(x^3-9x)/(3x^2-3x-6) is Vertical: x=-1,x=2,Slant: y= 1/3 x+1/3