What is the critical f(x)=(3x-1)(x-2)^4 ?

The critical f(x)=(3x-1)(x-2)^4 is x= 2/3 ,x=2

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critical f(x)=(3x-1)(x-2)^4

critical points

f (x) = (3 x - 1) (x - 2)^{4}

x = \frac{2}{3}, x = 2

Solution steps

(3 x - 1) (x - 2)^{4}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{2}{3}, x = 2

Identify critical points not in

f (x)

domain

Domain of

(3 x - 1) (x - 2)^{4} : - \infty < x < \infty

All critical points are in domain

x = \frac{2}{3}, x = 2

\frac{x ^{\frac{1}{3}} - a ^{\frac{1}{3}}}{x - a}

- \frac{x + 1}{∣ x + 1 ∣ - x ^{2} - 2 x}

f (x) = \frac{x - 2}{x ^{2} - 3}

f (x) = x^{2} + 7 x - 3

f (x) = - 9

What is the critical f(x)=(3x-1)(x-2)^4 ?
The critical f(x)=(3x-1)(x-2)^4 is x= 2/3 ,x=2