What is the critical f(x)=(2x)/(x^2-16) ?

The critical f(x)=(2x)/(x^2-16) is None

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critical f(x)=(2x)/(x^2-16)

critical points

f (x) = \frac{2 x}{x ^{2} - 16}

None

Solution steps

\frac{2 x}{x ^{2} - 16}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 4, x = 4

Identify critical points not in

f (x)

domain

Domain of

\frac{2 x}{x ^{2} - 16} : x < - 4 or - 4 < x < 4 or x > 4

\frac{2 x}{x ^{2} - 16}

is not defined at

x = - 4, x = 4

, therefore:

None

What is the critical f(x)=(2x)/(x^2-16) ?
The critical f(x)=(2x)/(x^2-16) is None