What is the critical (x^2+1)/(x^2-x-6) ?

The critical (x^2+1)/(x^2-x-6) is x=-7-5sqrt(2),x=5sqrt(2)-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

critical (x^2+1)/(x^2-x-6)

critical points

\frac{x ^{2} + 1}{x ^{2} - x - 6}

x = - 7 - 52, x = 52 - 7

Solution steps

\frac{x ^{2} + 1}{x ^{2} - x - 6}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 7 - 52, x = 52 - 7, x = - 2, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} + 1}{x ^{2} - x - 6} : x < - 2 or - 2 < x < 3 or x > 3

\frac{x ^{2} + 1}{x ^{2} - x - 6}

is not defined at

x = - 2, x = 3

, therefore:

x = - 7 - 52, x = 52 - 7

What is the critical (x^2+1)/(x^2-x-6) ?
The critical (x^2+1)/(x^2-x-6) is x=-7-5sqrt(2),x=5sqrt(2)-7