What is the critical f(x)=ln(x^3)-9x ?

The critical f(x)=ln(x^3)-9x is x= 1/3

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critical f(x)=ln(x^3)-9x

critical points

f (x) = ln (x^{3}) - 9 x

x = \frac{1}{3}

Solution steps

ln (x^{3}) - 9 x

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{3}, x = 0

Identify critical points not in

f (x)

domain

Domain of

ln (x^{3}) - 9 x : x > 0

ln (x^{3}) - 9 x

is not defined at

x = 0

, therefore:

x = \frac{1}{3}