What is the critical f(x)=x^{-1/3}(x-6) ?

The critical f(x)=x^{-1/3}(x-6) is x=-3

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critical f(x)=x^{-1/3}(x-6)

critical points

f (x) = x^{- \frac{1}{3}} (x - 6)

x = - 3

Solution steps

x^{- \frac{1}{3}} (x - 6)

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{- \frac{1}{3}} (x - 6) : x < 0 or x > 0

x^{- \frac{1}{3}} (x - 6)

is not defined at

x = 0

, therefore:

x = - 3

What is the critical f(x)=x^{-1/3}(x-6) ?
The critical f(x)=x^{-1/3}(x-6) is x=-3