What is the critical f(x)=((x^2-1))/(x^2+3x-4) ?

The critical f(x)=((x^2-1))/(x^2+3x-4) is None

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critical f(x)=((x^2-1))/(x^2+3x-4)

critical points

f (x) = \frac{( x ^{2} - 1 )}{x ^{2} + 3 x - 4}

None

Solution steps

\frac{x ^{2} - 1}{x ^{2} + 3 x - 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 4

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 1}{x ^{2} + 3 x - 4} : x < - 4 or - 4 < x < 1 or x > 1

\frac{x ^{2} - 1}{x ^{2} + 3 x - 4}

is not defined at

x = - 4

, therefore:

None

What is the critical f(x)=((x^2-1))/(x^2+3x-4) ?
The critical f(x)=((x^2-1))/(x^2+3x-4) is None