What is the critical f(x)=(4x)/(25-x^2) ?

The critical f(x)=(4x)/(25-x^2) is None

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critical f(x)=(4x)/(25-x^2)

critical points

f (x) = \frac{4 x}{25 - x ^{2}}

None

Solution steps

\frac{4 x}{25 - x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 5, x = 5

Identify critical points not in

f (x)

domain

Domain of

\frac{4 x}{25 - x ^{2}} : x < - 5 or - 5 < x < 5 or x > 5

\frac{4 x}{25 - x ^{2}}

is not defined at

x = - 5, x = 5

, therefore:

None

What is the critical f(x)=(4x)/(25-x^2) ?
The critical f(x)=(4x)/(25-x^2) is None