What is the critical f(x)=x^3+2xy-6x-4y^2 ?

The critical f(x)=x^3+2xy-6x-4y^2 is (4/3 , 1/3),(-3/2 ,-3/8)

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critical f(x)=x^3+2xy-6x-4y^2

critical points

f (x) = x^{3} + 2 x y - 6 x - 4 y^{2}

(\frac{4}{3}, \frac{1}{3}), (- \frac{3}{2}, - \frac{3}{8})

Solution steps

x^{3} + 2 x y - 6 x - 4 y^{2}

Find where

\nabla f (x, y)

is equal to zero or undefined

(\frac{4}{3}, \frac{1}{3}), (- \frac{3}{2}, - \frac{3}{8})

What is the critical f(x)=x^3+2xy-6x-4y^2 ?
The critical f(x)=x^3+2xy-6x-4y^2 is (4/3 , 1/3),(-3/2 ,-3/8)