What is the critical f(x)=x^4-12x^3+16x^2 ?

The critical f(x)=x^4-12x^3+16x^2 is x=0,x=1,x=8

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critical f(x)=x^4-12x^3+16x^2

critical points

f (x) = x^{4} - 12 x^{3} + 16 x^{2}

x = 0, x = 1, x = 8

Solution steps

x^{4} - 12 x^{3} + 16 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 1, x = 8

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 12 x^{3} + 16 x^{2} : - \infty < x < \infty

All critical points are in domain

x = 0, x = 1, x = 8

f (x) = \frac{x + 7}{x ^{3} - 3 x ^{2} + 5 x + 2}

\frac{x + 2}{x - 5}

5 x^{4} - 30 x^{2}

f (x) = \frac{( t + 1 )}{t}

f (x) = - x - 5

What is the critical f(x)=x^4-12x^3+16x^2 ?
The critical f(x)=x^4-12x^3+16x^2 is x=0,x=1,x=8