What is the critical f(x)= 2/(x^2-3x+2) ?

The critical f(x)= 2/(x^2-3x+2) is x= 3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

critical f(x)= 2/(x^2-3x+2)

critical points

f (x) = \frac{2}{x ^{2} - 3 x + 2}

x = \frac{3}{2}

Solution steps

\frac{2}{x ^{2} - 3 x + 2}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{3}{2}, x = 1, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{2}{x ^{2} - 3 x + 2} : x < 1 or 1 < x < 2 or x > 2

\frac{2}{x ^{2} - 3 x + 2}

is not defined at

x = 1, x = 2

, therefore:

x = \frac{3}{2}

What is the critical f(x)= 2/(x^2-3x+2) ?
The critical f(x)= 2/(x^2-3x+2) is x= 3/2