What is the critical f(x)=(3x^2)/(x-7) ?

The critical f(x)=(3x^2)/(x-7) is x=0,x=14

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critical f(x)=(3x^2)/(x-7)

critical points

f (x) = \frac{3 x ^{2}}{x - 7}

x = 0, x = 14

Solution steps

\frac{3 x ^{2}}{x - 7}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 14, x = 7

Identify critical points not in

f (x)

domain

Domain of

\frac{3 x ^{2}}{x - 7} : x < 7 or x > 7

\frac{3 x ^{2}}{x - 7}

is not defined at

x = 7

, therefore:

x = 0, x = 14

What is the critical f(x)=(3x^2)/(x-7) ?
The critical f(x)=(3x^2)/(x-7) is x=0,x=14