What is the critical 4/((1-4x^2)^2) ?

The critical 4/((1-4x^2)^2) is x=0

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critical 4/((1-4x^2)^2)

critical points

\frac{4}{( 1 - 4 x ^{2} ) ^{2}}

x = 0

Solution steps

\frac{4}{( 1 - 4 x ^{2} ) ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - \frac{1}{2}, x = \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

\frac{4}{( 1 - 4 x ^{2} ) ^{2}} : x < - \frac{1}{2} or - \frac{1}{2} < x < \frac{1}{2} or x > \frac{1}{2}

\frac{4}{( 1 - 4 x ^{2} ) ^{2}}

is not defined at

x = - \frac{1}{2}, x = \frac{1}{2}

, therefore:

x = 0