What is the critical f(x)=6x+9/x+2 ?

The critical f(x)=6x+9/x+2 is x=-sqrt(3/2),x=sqrt(3/2)

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critical f(x)=6x+9/x+2

critical points

f (x) = 6 x + \frac{9}{x} + 2

x = - \frac{3}{2}, x = \frac{3}{2}

Solution steps

6 x + \frac{9}{x} + 2

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{3}{2}, x = \frac{3}{2}, x = 0

Identify critical points not in

f (x)

domain

Domain of

6 x + \frac{9}{x} + 2 : x < 0 or x > 0

6 x + \frac{9}{x} + 2

is not defined at

x = 0

, therefore:

x = - \frac{3}{2}, x = \frac{3}{2}

What is the critical f(x)=6x+9/x+2 ?
The critical f(x)=6x+9/x+2 is x=-sqrt(3/2),x=sqrt(3/2)