What is the critical f(x)=-9/((x^2-9)sqrt(x^2-9)) ?

The critical f(x)=-9/((x^2-9)sqrt(x^2-9)) is None

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critical f(x)=-9/((x^2-9)sqrt(x^2-9))

critical points

f (x) = - \frac{9}{( x ^{2} - 9 ) x ^{2} - 9}

None

Solution steps

- \frac{9}{( x ^{2} - 9 ) x ^{2} - 9}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 3

Identify critical points not in

f (x)

domain

Domain of

- \frac{9}{( x ^{2} - 9 ) x ^{2} - 9} : x < - 3 or x > 3

- \frac{9}{( x ^{2} - 9 ) x ^{2} - 9}

is not defined at

x = - 3, x = 3

, therefore:

None

What is the critical f(x)=-9/((x^2-9)sqrt(x^2-9)) ?
The critical f(x)=-9/((x^2-9)sqrt(x^2-9)) is None