What is the inverse of (x^2-4)/(3x^2) ?

The inverse of (x^2-4)/(3x^2) is sqrt(-4/(3x-1)),-sqrt(-4/(3x-1))

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inverse of (x^2-4)/(3x^2)

inverse

\frac{x ^{2} - 4}{3 x ^{2}}

- \frac{4}{3 x - 1}, - - \frac{4}{3 x - 1}

Solution steps

y = \frac{x ^{2} - 4}{3 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 4}{3 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 4}{3 y ^{2}}

- \frac{4}{3 x - 1}, - - \frac{4}{3 x - 1}

f (x) = 0.1 x + 0.2

f (x) = - \frac{1}{2 8 - x}

\frac{1 + x}{1 - 2 x}

(- 2, 2), (5, 2)

f (x) = \frac{x}{3} - 2

What is the inverse of (x^2-4)/(3x^2) ?
The inverse of (x^2-4)/(3x^2) is sqrt(-4/(3x-1)),-sqrt(-4/(3x-1))