What is the critical f(x)=x^2ln(3x)+6 ?

The critical f(x)=x^2ln(3x)+6 is x= 1/(3sqrt(e))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

critical f(x)=x^2ln(3x)+6

critical points

f (x) = x^{2} ln (3 x) + 6

x = \frac{1}{3 e}

Solution steps

x^{2} ln (3 x) + 6

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{3 e}, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{2} ln (3 x) + 6 : x > 0

x^{2} ln (3 x) + 6

is not defined at

x = 0

, therefore:

x = \frac{1}{3 e}

What is the critical f(x)=x^2ln(3x)+6 ?
The critical f(x)=x^2ln(3x)+6 is x= 1/(3sqrt(e))