What is the critical f(x)=((3x-2))/(x^2-2x+1) ?

The critical f(x)=((3x-2))/(x^2-2x+1) is x= 1/3

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critical f(x)=((3x-2))/(x^2-2x+1)

critical points

f (x) = \frac{( 3 x - 2 )}{x ^{2} - 2 x + 1}

x = \frac{1}{3}

Solution steps

\frac{3 x - 2}{x ^{2} - 2 x + 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{3}, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{3 x - 2}{x ^{2} - 2 x + 1} : x < 1 or x > 1

\frac{3 x - 2}{x ^{2} - 2 x + 1}

is not defined at

x = 1

, therefore:

x = \frac{1}{3}

What is the critical f(x)=((3x-2))/(x^2-2x+1) ?
The critical f(x)=((3x-2))/(x^2-2x+1) is x= 1/3